Re: [PATCH] regulator: core: Still free GPIOs using gpio_free()

On Tue, Jul 01, 2014 at 12:55:26PM +0100, Mark Brown wrote:

From: Mark Brown broonie@linaro.org

Even though we mostly use GPIO descriptors internally we still use gpio_request_one() to request so we need to pair that with gpio_free() to release the GPIO.

Reported-by: Linus Walleij linus.walleij@linaro.org Signed-off-by: Mark Brown broonie@linaro.org

This doesn't explain the reason... I see the current GPIO code doing this:

void gpio_free(unsigned gpio) { gpiod_free(gpio_to_desc(gpio)); } EXPORT_SYMBOL_GPL(gpio_free);