We are saving first scheduling domain for a cpu in build_sched_domains() by iterating over the nested sd->child list. We don't actually need to do it this way.
*per_cpu_ptr(d.sd, i) is guaranteed to be NULL in the beginning as we have called __visit_domain_allocation_hell() which does a memset to zero for struct s_data.
So, save pointer to first SD while running the iteration loop over tl's.
Signed-off-by: Viresh Kumar viresh.kumar@linaro.org --- kernel/sched/core.c | 7 ++----- 1 file changed, 2 insertions(+), 5 deletions(-)
diff --git a/kernel/sched/core.c b/kernel/sched/core.c index 58453b8..638f6cb 100644 --- a/kernel/sched/core.c +++ b/kernel/sched/core.c @@ -6533,16 +6533,13 @@ static int build_sched_domains(const struct cpumask *cpu_map, sd = NULL; for (tl = sched_domain_topology; tl->init; tl++) { sd = build_sched_domain(tl, &d, cpu_map, attr, sd, i); + if (!*per_cpu_ptr(d.sd, i)) + *per_cpu_ptr(d.sd, i) = sd; if (tl->flags & SDTL_OVERLAP || sched_feat(FORCE_SD_OVERLAP)) sd->flags |= SD_OVERLAP; if (cpumask_equal(cpu_map, sched_domain_span(sd))) break; } - - while (sd->child) - sd = sd->child; - - *per_cpu_ptr(d.sd, i) = sd; }
/* Build the groups for the domains */