Currently, ghcb_alloc() always returns first entry. Fix it to return an unused entry.
Signed-off-by: Neeraj Upadhyay Neeraj.Upadhyay@amd.com --- tools/testing/selftests/kvm/lib/x86/sev.c | 3 +-- 1 file changed, 1 insertion(+), 2 deletions(-)
diff --git a/tools/testing/selftests/kvm/lib/x86/sev.c b/tools/testing/selftests/kvm/lib/x86/sev.c index 425ec8a3a3c7..228c446072a8 100644 --- a/tools/testing/selftests/kvm/lib/x86/sev.c +++ b/tools/testing/selftests/kvm/lib/x86/sev.c @@ -68,7 +68,6 @@ static void sev_es_terminate(void)
static struct ghcb_entry *ghcb_alloc(void) { - return &ghcb_pool->ghcbs[0]; struct ghcb_entry *entry; struct ghcb *ghcb; int i; @@ -81,7 +80,7 @@ static struct ghcb_entry *ghcb_alloc(void) entry = &ghcb_pool->ghcbs[i]; ghcb = &entry->ghcb;
- memset(&ghcb, 0, sizeof(*ghcb)); + memset(ghcb, 0, sizeof(*ghcb)); ghcb->ghcb_usage = 0; ghcb->protocol_version = 1;