On Wed, Sep 06, 2023 at 09:29:19AM +0000, Puranjay Mohan wrote:
On Tue, Sep 05 2023, Russell King (Oracle) wrote:
On Tue, Sep 05, 2023 at 09:06:19PM +0000, Puranjay Mohan wrote:
Actually, there can also be a situation where rd[1] != ARM_R0 && rd[1] != ARM_R2, so should I do it like:
if (rd[1] != ARM_R0 && rd[1] != ARM_R2) { emit(ARM_POP(BIT(ARM_R0) | BIT(ARM_R1)), ctx); emit(ARM_POP(BIT(ARM_R2) | BIT(ARM_R3)), ctx); } else if (rd[1] != ARM_R0) { emit(ARM_POP(BIT(ARM_R0) | BIT(ARM_R1)), ctx); emit(ARM_ADD_I(ARM_SP, ARM_SP, 8), ctx); } else if (rd[1] != ARM_R2) { emit(ARM_ADD_I(ARM_SP, ARM_SP, 8), ctx); emit(ARM_POP(BIT(ARM_R2) | BIT(ARM_R3)), ctx); } else { emit(ARM_ADD_I(ARM_SP, ARM_SP, 16), ctx); }
Are you sure all four states are possible?