I see nothing wrong, but perhaps this test can be simplified? Feel free to ignore.
Say,
On 06/27, Dev Jain wrote:
+void handler_usr(int signo, siginfo_t *info, void *uc) +{
- int ret;
- /*
* Break out of infinite recursion caused by raise(SIGUSR1) invoked
* from inside the handler
*/
- ++cnt;
- if (cnt > 1)
return;
- ksft_print_msg("In handler_usr\n");
- /* SEGV blocked during handler execution, delivered on return */
- if (raise(SIGSEGV))
ksft_exit_fail_perror("raise");
- ksft_print_msg("SEGV bypassed successfully\n");
You could simply do sigprocmask(SIG_SETMASK, NULL, &oldset) and check if SIGSEGV is blocked in oldset. SIG_SETMASK has no effect if newset == NULL.
Likewise,
- /*
* Mangle ucontext; this will be copied back into ¤t->blocked
* on return from the handler.
*/
- if (sigaddset(&((ucontext_t *)uc)->uc_sigmask, SIGUSR2))
ksft_exit_fail_perror("sigaddset");
+}
The caller (main) can do the same rather than raise(SIGUSR2).
But again, I won't insist.
Oleg.