I completely forgot when coming up with this type that #[derive(Default)] only works if all generics mentioned in the type implement Default (and T usually doesn't). This being said: We don't use `T` for anything besides using it for a reference type, so whether or not it implements `Default` shouldn't actually need to matter.
So, fix this by just manually implementing Default instead of deriving it.
Signed-off-by: Lyude Paul lyude@redhat.com --- rust/kernel/drm/gem/shmem.rs | 11 ++++++++++- 1 file changed, 10 insertions(+), 1 deletion(-)
diff --git a/rust/kernel/drm/gem/shmem.rs b/rust/kernel/drm/gem/shmem.rs index 843869056b1d7..d8bda8c8e2fb2 100644 --- a/rust/kernel/drm/gem/shmem.rs +++ b/rust/kernel/drm/gem/shmem.rs @@ -50,7 +50,6 @@ /// /// This is used with [`Object::new()`] to control various properties that can only be set when /// initially creating a shmem-backed GEM object. -#[derive(Default)] pub struct ObjectConfig<'a, T: DriverObject> { /// Whether to set the write-combine map flag. pub map_wc: bool, @@ -61,6 +60,16 @@ pub struct ObjectConfig<'a, T: DriverObject> { pub parent_resv_obj: Option<&'a Object<T>>, }
+impl<'a, T: DriverObject> Default for ObjectConfig<'a, T> { + #[inline(always)] + fn default() -> Self { + Self { + map_wc: false, + parent_resv_obj: None, + } + } +} + /// A shmem-backed GEM object. /// /// # Invariants